Paper Pattern and Exam schedule for WBJEEM 2015

exams

About WBJEEM-

The West Bengal Joint Entrance Examinations Board (WBJEEM) 2015 is an entrance examination conducted for the admission to undergraduate (UG) courses of Bachelor of Engineering (BE)/Bachelor of Technology (B Tech)/Bachelor of Architecture (B Arch)/Bachelor of Pharmacy (B Pharm) as well as Bachelor of Medicine & Bachelor of Surgery (MBBS)/Bachelor of Dental Surgery (BDS) offered by colleges and universities in the state of West Bengal.

The exam for 2015 will be held on April 18 and 19, 2015.

Exam schedule-

  • On April 18th 2015, Biological Sciences (150 marks) timings will be 1pm to 4 pm.
  • On April 19th 2015, Mathematics (100 marks) timings will be 12 noon to 2 pm and Physics- Chemistry (100 marks) timings-3pm to 5 pm

Questions will be based on the published syllabus for WBJEEM 2015.

In every subject, all questions will be Multiple Choice Questions (MCQ-type, with four options against each of the questions) and the answer(s) to each of the questions has to be marked on the OMR.

The paper pattern for the WBJEEM 2015 is as follows:

The examination will be conducted on three papers: Biological Science, Mathematics, and Physics & Chemistry (Combined).

Each paper will be of MCQ type containing three categories of questions.
Category 1
Only one option is correct, correct response will yield one mark Only one option is correct, correct response will yield one mark.
For incorrect response, 25 % of full mark (1/4) would be deducted and
For more than one answer indicated against a particular question in the OMR sheet; the said answer will be treated as incorrect response/answer.

Category 2:
Only one option is correct, correct response will yield two marks.
For incorrect response, 25% of full marks (1/2) would be deducted and
For more than one answer indicated against a particular question in the OMR sheet; the said answer will be treated as incorrect response/answer.

Category 3:
More than one option may be correct and marking of all correct options only will yield two marks.
For any combination of answers containing one or more incorrect responses, net
mark awarded will be zero (0) and
For partially correct response without any incorrect marking: Marks awarded = 2 x (no of correct responses) / (total no of correct options).

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